
  






  








COMENTÁRIO DA PROVA - MATEMÁTICA




  



 

 

 

 




 







COMENTÁRIO
- ASSUNTO: FUNÇÃO TRIGONOMÉTRICA





2 . sen2x – 3 senx + 1 = 0
 

− ( − 3) ± ( − 3)2 − 4 . 2 . 1
 

senx =
2.2
 

 
3± 1 3±1

=
senx =
4
4




1
senx
=
1
ou
senx
=
.

2



1

2
,

• Admitindo que senp = 1 e senq = 2 teremos cos
 q = ±

3 1


Daí sen2p – cos2q = 12 – = = 0,25.
4
2
3
3
 = .
2 
4
4
1

• Admitindo que senp = 2 e senq = 1, teremos cos2q = 0.

 1 2
1
Daí sen2p – cos2q =  2  – 0 = 4 = 0,25.
Item: B
Download

m13 - Christus